2.7 DNA'Replication,'Transcription'and'Translation'
DNA'Replication'
!"#$%&'()*+(,-.(/0#$&1%2&*'(&3(304&51*'30/6%2&60(
…………………………………………………………………………………………………………………………………………………..........#
…………………………………………………………………………………………………………………………………………………..........#
…………………………………………………………………………………………………………………………………………………..........#
(
782$&'0()*+(2)0(/038$23(*9(2)0(:030$3*'5;2%)$(0"#0/&40'2(38##*/20<(304&51*'30/6%2&60(,-.(/0#$&1%2&*'(
…………………………………………………………………………………………………………………………………………………..........#
…………………………………………………………………………………………………………………………………………………..........#
…………………………………………………………………………………………………………………………………………………..........#
…………………………………………………………………………………………………………………………………………………..........#
…………………………………………………………………………………………………………………………………………………..........#
(
,031/&=0(2)0(/*$0(*9(2)0(9*$$*+&'>(0'?@403(&'(,-.(/0#$&1%2&*'(
Helicase:##…………………………………………………………………………………………………………………………………………#
…………………………………………………………………………………………………………………………………………………..........#
…………………………………………………………………………………………………………………………………………………..........#
DNA#Polymerase:##…………………………………………………………………………………………………………………………….#
…………………………………………………………………………………………………………………………………………………..........#
…………………………………………………………………………………………………………………………………………………..........#
#
!"#$%&'(2)0(3&>'&9&1%'10(*9(1*4#$040'2%/@(=%30(#%&/&'>(&'(2)0(1*'30/6%2&*'(*9(=%30(30A80'10(
…………………………………………………………………………………………………………………………………………………..........#
…………………………………………………………………………………………………………………………………………………..........#
…………………………………………………………………………………………………………………………………………………..........#
#
;2%20(+)0'(%'<(+)0/0(,-.(/0#$&1%2&*'()%##0'3(&'(%(2@#&1%$(08B%/@*2&1(10$$(
…………………………………………………………………………………………………………………………………………………..........#
Meselson and Stahl treated DNA with a heavier nitrogen isotope (15N) and then replicated in the presence
of a lighter nitrogen isotope (14N) - so template DNA and newly synthesised DNA could be differentiated.
The results supported a semi-conservative model of DNA replication:
• After one division, all molecules contained both 15N and 14N
• After two divisions, some molecules contained both 15N and 14N, while other molecules only contained 14N
Free nucleotides can only align opposite their complementary base partner (A=T, G=C)
This means a newly synthesised strand will be identical to the complementary partner of a template strand
Hence, base sequence is conserved